Okay this my last one can y'all help
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a. The solution is (0,2)
b. The first expression will be easier to substitute as in the first expression the variable y is already isolated on one side of the equation so we can easily put 5x+2 in place of y in equation 2.
Step-by-step explanation:
Given equations are:
[tex]y = 5x+2\ \ \ \ Eqn1\\12.5x+2.5y = 5\ \ \ \ Eqn2[/tex]
a. Solution
Putting y = 5x+2 in equation 2
[tex]12.5x+2.5(5x+2) = 5\\12.5x+12.5x+5 = 5\\25x +5 = 5\\25x = 5-5\\25x = 0\\x = 0[/tex]
Putting x = 0 in equation 1
[tex]y = 5(0)+2\\= 0+2 = 2[/tex]
Hence,
The solution is (0,2)
b: Reason:
The first expression will be easier to substitute as in the first expression the variable y is already isolated on one side of the equation so we can easily put 5x+2 in place of y in equation 2.
Keywords: Linear equation, substitution
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