Respuesta :

Completing the square gives

[tex]x^2+3x-6=x^2+3x+\dfrac94-\dfrac{33}4=\left(x+\dfrac32\right)^2-\dfrac{33}4[/tex]

Then

[tex]f(x)=\left(x+\dfrac32\right)^2-\dfrac{33}4\ge0-\dfrac{33}4=-\dfrac{33}4[/tex]

and -33/4 = -8.25, so your answer is correct.

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