In an acid-base titration, a base or acid is gradually added to the other until they have completely neutralized each other. Since acids and bases are usually colorless (as are the water and salt produced in the neutralization reaction), pH is measured to monitor the reaction. Suppose that the equivalence point is reached after approximately 100 mL of a NaOH solution have been added (enough to react with all the acetic acid present) but that replicates are equally likely to indicate from 95 to 104 mL to the nearest mL. Assume that volumes are measured to the nearest mL and describe the sample space. Round your answers to one decimal place (e.g. 98.7). a) What is the probability that equivalence is indicated at 100 mL?

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Answer:

1/10 or 0.1

Explanation:

Quantities at which equivalence can be obtained are:

           

95, 96, 97, 98, 99, 100, 101, 102, 103, 104

Number of quantities = N = 10

Probability that the equivalency is obtained exactly at 100 mL can be calculated as follows:

P(X = 100) =  (Number of favourable outcomes) / (Total Number of Outcomes)

P(X = 100) = 1/10

P(X = 100) = 0.1

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