Step-by-step explanation:
[tex]Km+5x=6y\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\Km+5x-5x=6y-5x\\\\Km=6y-5x\qquad\text{divide both sides by}\ K\neq0\\\\\dfrac{Km}{K}=\dfrac{6y-5x}{K}\\\\\huge\boxed{m=\dfrac{6y-5x}{K}}[/tex]
