Answer:
a.) The dilation is a contraction
b.) The scale factor is [tex]\frac{6}{8} = \frac{3}{4} = 0.75[/tex] which is less than 1
c.) [tex]\frac{TA}{TR} = \frac{3.33}{TR} = 0.75 \hspace{0.2cm} \Rightarrow \hspace{0.2cm} TR = \frac{3.3}{0.75} \hspace{0.2cm} \Rightarrow \hspace{0.2cm} TR = 4.4 cm.[/tex]
[tex]\therefore TR = TA + AR \hspace{0.2cm} \Rightarrow \hspace{0.2cm} AR = 4.4 - 3.3 = 1.1 cm[/tex]
d.)[tex]\frac{TN}{TI} = \frac{TN}{TN + 1.6} = 0.75 \hspace{0.1cm} \Rightarrow \hspace{0.1cm} 1.33TN = TN + 1.6 \hspace{0.1cm} \Rightarrow \hspace{0.1cm} 0.33TN = 1.6 cm. \hspace{0.1cm}[/tex]
Therefore TN = 4.8 cm
Step-by-step explanation:
a.) The dilation is a contraction
b.) The scale factor is [tex]\frac{6}{8} = \frac{3}{4} = 0.75[/tex] which is less than 1
c.) [tex]\frac{TA}{TR} = \frac{3.33}{TR} = 0.75 \hspace{0.2cm} \Rightarrow \hspace{0.2cm} TR = \frac{3.3}{0.75} \hspace{0.2cm} \Rightarrow \hspace{0.2cm} TR = 4.4 cm.[/tex]
[tex]\therefore TR = TA + AR \hspace{0.2cm} \Rightarrow \hspace{0.2cm} AR = 4.4 - 3.3 = 1.1 cm[/tex]
d.)[tex]\frac{TN}{TI} = \frac{TN}{TN + 1.6} = 0.75 \hspace{0.1cm} \Rightarrow \hspace{0.1cm} 1.33TN = TN + 1.6 \hspace{0.1cm} \Rightarrow \hspace{0.1cm} 0.33TN = 1.6 cm. \hspace{0.1cm}[/tex]
Therefore TN = 4.8 cm
