Question

In a region where there is a uniform electric field, the potential, V1, is 1.3 V at position y1=26 cm. At position y2=28 cm, the potential, V2, is 3.9 V. What is the magnitude of the y-component of the electric field in this region?

Answer 1

Answer:

1.3 V/cm

Explanation:

We are given that

Potential=$V_1=1.3 V,y_1=26cm$

$V_2=3.9 V,y_2=28 cm$

We have to find the magnitude of y-component of the electric field in this region.

We know that

$E=\mid\frac{\Delta V}{\Delta y}\mid$

Using the formula

$E=\mid\frac{V_2-V_2}{y_2-y_1}\mid=\mid\frac{3.9-1.3}{28-26}\mid$

$E=\mid\frac{2.6}{2}\mid=1.3V/cm$

Hence, the magnitude of the y-component of the electric field in this region=1.3 V/cm

Answer 2

The magnitude of the y-component of the electric field in this region is 1.3 V/cm.

Calculation of magnitude:

Since  V1 is 1.3 V at position y1=26 cm. At position y2=28 cm, the potential, V2, is 3.9 V

So,

We know that

$E = \frac{V_2- V_1}{Y_2-Y_1}\\\\ = \frac{3.9-1.3}{28-26}\\\\ = \frac{2.6}{2}$

=  1.3 V/cm

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