Determine the mass in grams of potassium chloride that must be added to 97 g of water to make a 1.09 m solution. Enter your answer to 2 decimal places.

Respuesta :

Answer: 7.88 grams

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

[tex]Molarity=\frac{n}{W_s}[/tex]

where,

n = moles of solute

 [tex]W_s[/tex] = weight of solvent in kg

moles of solute =[tex]\frac{\text {given mass}}{\text {molar mass}}=\frac{xg}{74.5g/mol}[/tex]

mass of solvent = 97 g = 0.097 kg    (1kg=1000g)

Now put all the given values in the formula of molality, we get

[tex]1.09=\frac{x}{74.5g/mol\times 0.097kg}[/tex]

[tex]x=7.88g[/tex]

Therefore, the mass in grams of potassium chloride that must be added to 97 g of water to make a 1.09 m solution is 7.88

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