When Michael Wilson of the Harlem Globetrotters slam- dunked a basketball 12 feet, his hang time for the shot was approximately 1.16 seconds. What was the vertical distance of his jump, rounded to the nearest tenth of a foot?

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Answer:

5.4 feet.

Step-by-step explanation:

We have been given that when Michael Wilson of the Harlem Globetrotters slam- dunked a basketball 12 feet, his hang time for the shot was approximately 1.16 seconds. We are asked to find vertical distance of his jump.

We will use formula [tex]t=\frac{\sqrt{d}}{2}[/tex] to solve our given problem, where, 't' represents hang time of a player and 'd' represents vertical distance of a player's jump.

Upon substituting [tex]t=1.16[/tex] in above formula, we will get:

[tex]1.16=\frac{\sqrt{d}}{2}[/tex]

Multiply both sides by 2:

[tex]1.16*2=\frac{\sqrt{d}}{2}*2[/tex]

[tex]2.32=\sqrt{d}[/tex]

Now, we will square both sides of our equation as:

[tex]2.32^2=(\sqrt{d})^2[/tex]

[tex]5.3824=d[/tex]

Round to nearest tenth of a foot:

[tex]d\approx 5.4[/tex]

Therefore, the vertical distance of Wilson's jump was approximately 5.4 feet.

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