Question

A box is attached to a horizontal spring and compressed 0.2 meters. The spring constant is 20 N/m. What is the force from the spring once the spring is compressed?

Answer 1

The force on the spring is 4 N

Explanation:

The force exerted on a spring is given by Hooke's law:

$F=kx$

where:

F is the force

k is the spring constant

x is the elongation of the spring

For the spring in this problem, we have:

k = 20 N/m (spring constant)

x = 0.2 m (compression of the spring)

Solving for F, we find the force on the spring:

$F=(20)(0.2)=4 N$

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