Question

Displacement vectors of 4 km south, 2 km north, 5 km south, and 5 km north combine to a
total displacement of
16 km north.
11 km west.
6km south.
2 km south

Answer 1

Answer:

The displacement = 2 km south.

Explanation:

Given:

Displacement vectors.

• (i) Of 4 km south.
• (ii) 2 km north.
• (iii) 5 km south.
• (iv) 5 km north.

Total displacement :Displacement is the shortest distance from the initial point of any vector.

We have to work this in a Cartesian co-ordinate where we have y axis as North and South (negative y-axis).

Lets move 4 km towards south that is 4 units on negative y-axis.

The points will be $(0,-4)$.

Now move 2 km upward (towards north) that is toward positive y-axis.

So the points are $(0,-2)$.

From here again 5 km downward (towards south).

Points of the co-ordinates are $(0,-7)$.

Finally move 5 km upwards (towards north).

Points of the Cartesian are $(0,-2)$.

So (0,-2) means that the displacement vector is toward south and is 2 km way from the origin that is $(0,0)$.

Total displacement is of 2 km in south.