Respuesta :
Answer:
Part a: The force between the tires and the ground is 765 lbf.
Part b: The force between the pallet and the boulder is 1016 lbf.
Explanation:
From the free body diagram on the Truck, boulder and pallet level
- [tex]a_T[/tex] is the acceleration of truck which is 1 ft/s2
- [tex]m_T[/tex] is the mass of the truck which is 5000 lb or 155.28 slugs
- [tex]m_b[/tex] is the mass of the boulder which is 1000 lb or 31.06 slugs
- [tex]m_a[/tex] is the mass of the pallet which is 200 lb or 6.211 slugs
- [tex]a_a =a_b[/tex] is the acceleration of the pallet or boulder which is 0.5 ft/s2
Applying Newton's 2nd Law of Motion on pulley in vertical direction
[tex]2T-(m_a+m_b)g=(m_a+m_b)a_a\\2T-(37.271)(32.2)=(37.271)(0.5)\\T=609.32 lb_f[/tex]
Part a
Applying Newton's 2nd Law of Motion on Truck in horizontal direction
[tex]F-T=m_Ta_T\\F=609.32+(155.28)(1)\\F=765 lb_f[/tex]
So the force between the tires and the ground is 765 lbf.
Part b
Applying Newton's 2nd Law of Motion on Boulder in vertical direction
[tex]F_{AB}-m_bg=m_ba_b\\F_{AB}=m_b(g+a_b)\\F_{AB}=31.056(32.2+0.5)\\F_{AB}=1016 lb_f[/tex]
So the force between the pallet and the boulder is 1016 lbf.


