Respuesta :
Answer:
C4H10O(l) + 6O2(g) → 4CO2(g) + 5H2O(g)
Explanation:
Step 1: Data given
Combustion of C4H10O means adding oxygen gas
Step 2: Balancing the equation
C4H10O(l) + O2(g) → CO2(g) + H2O(g)
On the left side we hace 4x C, on the right side we have 1x C. To balance the amount of C, we have to multiply CO2 (on the right) by 4.
C4H10O(l) + O2(g) → 4CO2 (g)+ H2O(g)
On the left side we have 10x H, on the right side we have 2x H. To balance the amount of H, we have to multiply H2O (on the right side) by 5.
C4H10O(l) + O2(g) → 4CO2(g) + 5H2O(g)
On the left side we 3x O (1x in C4H10O and 2x in O2) on the right side we have 13x O (8x in CO2 and 5x in H2O). To balance the amount of o on both sides, we have to multiply O2 (on the left side) by 6.
Now the equation is balanced.
C4H10O(l) + 6O2(g) → 4CO2(g) + 5H2O(g)
The balanced equation for the combustion of 1 mole of C₄H₁₀O is:
C₄H₁₀O(l) + 6O₂(g) —> 4CO₂(g) + 5H₂O(g)
A combustion reaction is a reaction in which a substance is burned in air (oxygen) to produce carbon dioxide and water.
The equation for the combustion of 1 mole of C₄H₁₀O can be written as follow:
C₄H₁₀O(l) + O₂(g) —> CO₂(g) + H₂O(g)
The above equation can be balance as illustrated below:
C₄H₁₀O(l) + O₂(g) —> CO₂(g) + H₂O(g)
Therefore are 4 atoms of C on the left side and 1 atom on the right side. It can be balance by writing 4 before CO₂ as shown below:
C₄H₁₀O(l) + O₂(g) —> 4CO₂(g) + H₂O(g)
There are 10 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 5 before H₂O as shown below:
C₄H₁₀O(l) + O₂(g) —> 4CO₂(g) + 5H₂O(g)
There are 3 atoms of O on the left side and a total of 13 atoms on the right side. It can be balance by writing 6 before O₂ as shown below:
C₄H₁₀O(l) + 6O₂(g) —> 4CO₂(g) + 5H₂O(g)
Now, the equation is balanced.
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