Respuesta :
Answer:
the cross-sectional area is 58.63 m²
Step-by-step explanation:
the cross-section of a cylinder perpendicular to its length is a circle whose radius is the cylinder's radius. Thus the corresponding area A is
A= π*R² = π*(4.32 m)² = 58.63 m²
therefore the cross-sectional area is 58.63 m²
Answer:
CSA = 58.63 m^2
Therefore, the cross-sectional area perpendicular to its length is 58.63 m^2
Step-by-step explanation:
The cross sectional area of a cylinder that is perpendicular (that means at angle 90°) to the length of the cylinder is the area of the circular top of the cylinder when viewing the cylinder from the top. It can be expressed mathematically as ;
CSA = πr^2 .....1
Where r is the radius of the cylinder.
Given;
radius r = 4.32 m
length l = 9.00 m
Substituting the value of r into equation 1;
CSA = π × (4.32)^2
CSA = 58.63 m^2
Therefore, the cross-sectional area perpendicular to its length is 58.63 m^2
