a raindrop has a mass of 50 mg and the pacific ocean has mass of 7.08X10^20kg

1)what is the mass of 1 mole of a raindrop?

2)how many moles of raindrops have a mass equal to the mass of the pacific ocean?

Respuesta :

Answer:

1. Mass of 1 mole of raindrop: 301.10 x 10²⁰ kg

2. The number of moles of raindrops with the mass equal the the mass of Pacific ocean: 0.02351 mol

Explanation:

A mole contains 6.02214076×10²³ or roughly 6.022 x 10²³ particles, the number of 6.02214076×10²³ is called Avogadro's number.

1. A mole of raindrop has 6.022×10²³ raindrops, so the mass of 1 mole of raindrops is

M = 50 mg x 6.022 x 10²³ = 301.1 x 10²³ mg = 301.10 x 10²⁰ kg

2. The mass of the Pacific Ocean is 7.08 x 10²⁰ kg, so the moles of raindrop with the equal mass is 0.02351 mol

[tex]n = \frac{m}{M} = \frac{7.08 . 10^{20} }{301.10 . 10^{20} } = 0.02351 mol[/tex]

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