Answer:
A= Q/4 B=0 C=Q/4
Explanation:
The initial condition, is as follows:
A=Q B=0 C=0
When A is brought to contact with B, as both spheres are conductors, charge distribute evenly between the two spheres, so after this, the charges on the spheres are as follows:
A= Q/2 B=Q/2 C=0
If B touches C, while C is grounded, this supplies a infinite source of sink of charge, so both spheres lose any charge.
At this stage, the charge distribution is as follows:
A = Q/2 B=0 C=0
Assuming C is not grounded, when finally touches A, the charge on A distributes evenly between A and C, so the final situation is as follows:
A = Q/4 B=0 C=Q/4
