Answer:
[tex]\frac{15}{28}[/tex]
Step-by-step explanation:
Given that a bag contains 3 white and 5 black balls. Bob draws two balls one after another from the bag, without replacement.
Drawing one ball white and one black can be done in
[tex]3C1 *5C1\\= 15[/tex]
Total no of ways of drawing any two balls without replacement
= [tex]8C2\\[/tex]
= 28
the probability that any one ball is white and the other is black
= favourable outcomes/total outcomes
= [tex]\frac{15}{28}[/tex]
