Electrical force between the two charges is [tex]-4\cdot 10^9 N[/tex] (attractive)
Explanation:
The magnitude of the electrostatic force between two charged particles is given by Coulomb's law:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where:
[tex]k=8.99\cdot 10^9 Nm^{-2}C^{-2}[/tex] is the Coulomb's constant
[tex]q_1, q_2[/tex] are the charges of the two particles
r is the separation between the two particles
In this problem, we have:
[tex]q_1=+2C[/tex] is the charge of the first particle
[tex]q_2=-2C[/tex] is the charge of the second particle
r = 3 m is the separation between them
Substituting into the formula, we find the force:
[tex]F=(8.99\cdot 10^9)\frac{(+2)(-2)}{3^2}=-4\cdot 10^9 N[/tex]
And the negative sign means the force is attractive (the electric force between two charges with opposite sign is attractive)
Learn more about electric force:
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