Answer: [tex]74.1^0C[/tex]
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
[tex]Q=m\times c\times \Delta T[/tex]
Q = Heat absorbed=[tex]8.94\times 10^3[/tex] Joules
m= mass of copper = 454 g
c = specific heat capacity = [tex]0.385J/g^0C[/tex]
Initial temperature of the copper = [tex]T_i[/tex] = 23.0°C
Final temperature of the water = [tex]T_f[/tex] = ?
Change in temperature ,[tex]\Delta T=T_f-T_i[/tex]
Putting in the values, we get:
[tex]8.94\times 10^3=454\times 0.385\times (T_f-23.0)^0C[/tex]
[tex]T_f=74.1^0C[/tex]
The final temperature of copper will be [tex]74.1^0C[/tex]
