Question

A tow truck drags a stalled car along a road. The chain makes an angle of 30° with the road and the tension in the chain is 1000 N. How much work is done by the truck in pulling the car 1 km? (Round your answer to the nearest ten thousand.) joules

Answer 1

To develop this problem it is necessary to apply the work theorem. This tells us that the energy on a body is equivalent to the product between the Force applied on it and the distance traveled. The vector product of these measures can be expressed as

$W = \vec{F}\times \vec{x}$

And its magnitude is equivalent to

$W = Fx cos\theta$

Where $\theta$ is the angle formed between the applied force and the line of displacement of the body.

Our values are given as,

$\theta = 30\°$

$F= 1500N$

$x = 1000m$

Applying this value and replacing we have,

$W = Fxcos\theta$

$W = (1500)(1000)cos(30)$

$W = 1.299*10^6J$

Therefore the work done by the truck is 1.299 Mega Jules

Answer 2

The work done by the truck in pulling the car for 1 km is $1.299\times 10^5\;\rm J$.

Work

The movement of an object over a certain distance, by an external force applied in the direction of the displacement results in the transfer of energy which is measured as work done by the object. If the angle θ is the angle between the applied force and displacement, then work can be given as below.

$W = F\times d\times cos\theta$

Where w is the work done, f is the applied force, and d is the displacement.

Given that angle is 30 degrees, Force F is 1500 N and d is 1 km. Substituting the values in the above equation,

$W = 1500 \times 1\times 1000\times cos 30^\circ$

$W = 1299000\;\rm J$

$W = 1.299\times 10^5\;\rm J$

Hence we can conclude that the work done by the truck in pulling the car for 1 km is $1.299\times 10^5\;\rm J$.

To know more about the work, follow the link given below.

https://brainly.com/question/3902440.