Answer:
The compound inequality:
30 ≤ 2L + 2w ≤ 64
w < 12
The range:
3 ≤ w < 12
Step-by-step explanation:
Let L be he length , w the width and p the perimeter
p=2L + 2w
30 ≤ p ≤ 64 ⇌ 30 ≤ 2L + 2w ≤ 64 ⇌ 30 ≤ 24 + 2w ≤ 64 ⇌ 6 ≤ 2w ≤ 40
⇌ 3 ≤ w ≤ 20
but ,since the width is less than the length then w < 12
then 3 ≤ w < 12