Answer:
x = 18 & y = 5
Step-by-step explanation:
GIVEN ;
Δ ABD [tex]\sim[/tex] Δ ACE .
So by using the properties of similarity ,
[tex]\frac{AC}{AB} = \frac{EC}{BD} = \frac{AE}{DE} = \frac{9+x}{9} = \frac{33}{11} = \frac{15}{y}[/tex]
[tex]\frac{9 + x}{9} = \frac{33}{11}[/tex]
⇒ x = 18 .
Similarly ,
[tex]\frac{15}{y} = \frac{33}{11}[/tex]
⇒ y =5 .
