The 50th term of geometric sequence is [tex]5(3)^{49}[/tex]
Solution:
Given that, geometric sequence starts 5, 15, . . . .
To find: 50th term
Given is a geometric sequence
Let us find the common ratio between terms
The common ratio is the ratio of a term to the previous term
[tex]r = \frac{15}{5} = 3[/tex]
The formula for nth term of geometric sequence is given by:
[tex]a_n = ar^{n-1}[/tex]
Where,
[tex]a_n[/tex] is the nth term of sequence
a is the first term of sequence
r is the common ratio
In the given sequence,
first term = a = 5
r = 3
Substituting the values we get,
[tex]a_n = 5(3)^{n-1}[/tex]
To find the 50th term, substitute n = 50
[tex]a_{50} = 5(3)^{50-1}\\\\a_{50} = 5(3)^{49}\\\\[/tex]
Thus the 50th term is found