Question

An astronaut drops a hammer from 2.0 meters above the surface of the Moon. If the acceleration due to gravity on the Moon is 1.62 meters per second2, how long will it take for the hammer to fall to the Moon’s surface?

A. 0.62 s
B. 1.2 s
C. 1.6 s
D. 2.5 s

Answer 1

Answer:

option C

Explanation:

given,

height of the hammer, h = 2 m

acceleration due to gravity of the moon, g = 1.62 m/s²

time taken by the hammer to reach at bottom = ?

initial speed of the hammer, u = 0 m/s

using equation of motion for the time calculation

$s = ut + \dfrac{1}{2}gt^2$

$2 = 0+\dfrac{1}{2}\times 1.62\times t^2$

    t² = 2.469

     t = 1.57 s ≅ 1.6 s

hence, the time taken by the hammer to reach the bottom is equal to 1.6 s.

The correct answer is option C