Answer:
a) [tex]population\hspace{0.1cm} mean = \frac{64 + 77 + 89 + 69 + 89 + 65 + 88 + 69 + 87}{9} = 77.44[/tex]
b)[tex]sample\hspace{0.1cm} mean 1 = \frac{65 + 69 + 77}{3} = 70.3[/tex]
[tex]sample\hspace{0.1cm} mean 2 = \frac{64 + 69 + 77}{3} = 70[/tex]
c) both the means of the two samples underestimate the population mean.
the mean pulse rate of sample 1 underestimates the population mean.
the mean pulse rate of sample 2 underestimates the population mean.
Step-by-step explanation:
i) population size, N = 9
a) [tex]population\hspace{0.1cm} mean = \frac{64 + 77 + 89 + 69 + 89 + 65 + 88 + 69 + 87}{9} = 77.44[/tex]
b)[tex]sample\hspace{0.1cm} mean 1 = \frac{65 + 69 + 77}{3} = 70.3[/tex]
[tex]sample\hspace{0.1cm} mean 2 = \frac{64 + 69 + 77}{3} = 70[/tex]
c) both the means of the two samples underestimate the population mean.
the mean pulse rate of sample 1 underestimates the population mean.
the mean pulse rate of sample 2 underestimates the population mean.