Answer: g = acceleration = A*w^2 = A*(2*pi*fb)^2.
Explanation:
The ball bounces when the acceleration of the ball exceeds that of gravity. If A and fb are measured at that point, g = acceleration = A*w^2 = A*(2*pi*fb)^2.
The speed of the bounce increases slowly with the increase in the critical frequency of the ball.
The g is the gravitational acceleration of the ball which increases slowly.
The gravitational acceleration is the acceleration of an object in free fall within a vacuum. This is the steady gain in speed caused exclusively by the force of gravitational attraction.
Let us consider that fb is the critical frequency of the ball which has an amplitude of A. At some point, the gravitational acceleration of the ball can be given as below.
[tex]g = A\times (2\pi\times f_b)^2[/tex]
Here, the acceleration of the ball depends on the frequency of the ball bounce.
Hence we can conclude that if the value of fb increases, the speed of the bounce increases slowly.
To know more about gravitational acceleration, follow the link given below.
https://brainly.com/question/14374981.
