Question

3. For the reaction whose balanced equation is as follows, find the number of
grams of Iz that will be formed when 300.0 9 of bromine react.
2 KI + Br2 → 2 KBr + I2

Answer 1

Answer:

The mass of iodine produced in grams is :

= 476.605 grams of I2

Explanation:

Molar mass : It is the mass in gram present in 1 mole of the compound.

The atomic mass of Br = 79.904 g/mol

So , molar mass of Br2 = 2(mass of Br) = 2(79.04) = 159.808 gram

1 mole of Br2 = 159.808 gram

Atomic Mass of I = 126.904 gram

Mass of I2 = 2(mass of I) = 2(126.904)

Mass of I2 = 253.808 gram

1 mole of I2 = 253.808 gram

The balanced reaction is :

$2KI(s)+Br_{2}(l)\rightarrow 2KBr+I2$

According to this reaction ,

1 mole of Br2 will give = 1 mole of I2

159.808 gram of Br2 = 253.808 gram

So , 1 gram of Br2 =

$\frac{253.808}{159.808}$ of I2

(Always calculate first for 1 gram by dividing )

300.09 gram of Bromine will produce =

$\frac{253.808}{159.808}\times 300.09$

= 476.605 grams of I2