all my points! Calculate the change in free energy if 1.12 moles of Nal is dissolved in water at 25.0°C.

Answer:
Free energy change is -7.500248 kJ/mol
Explanation:
If we have the enthalpy change and entropy change, we can find the free energy change using the equation,
ΔG = ΔH - TΔS
Temperature in K = 25°C + 273 = 298 K
ΔH for NaI = -7.50 kJ/mol
ΔS for NaI = 74 J/K mol = 0.074 kJ/K mol
Plugin the above values in the equation, we will get,
ΔG = -7.5 kJ/mol - 0.074 kJ/K mol / 298 K
= -7.5 kJ/mol - 0.000248 kJ/mol
= -7.500248 kJ/mol
Answer:
Free energy change is -7.500248 kJ/mol
Explanation:
If we have the enthalpy change and entropy change, we can find the free energy change using the equation,
ΔG = ΔH - TΔS
Temperature in K = 25°C + 273 = 298 K
ΔH for NaI = -7.50 kJ/mol
ΔS for NaI = 74 J/K mol = 0.074 kJ/K mol
Plugin the above values in the equation, we will get,
ΔG = -7.5 kJ/mol - 0.074 kJ/K mol / 298 K
= -7.5 kJ/mol - 0.000248 kJ/mol
= -7.500248 kJ/mol