Question

Line k has a slope of -5. Line i is perpendicular to line k and passes through the point (5,9). Create the equation for line j.

Answer 1

Answer:

Therefore the equation of the line required is given by $y = \frac{1}{5} x + 8$

Step-by-step explanation:

i) Line k has a slope of $m_{1}$ is equal = -5

ii) Line i is perpendicular to line k and passes through the point (5,9)

  Let the slope of line i be $m_{2}$.

 Therefore $m_{1} \times m_{2} = -1 \Rightarrow m_{2}\times (-5) = -1 \therefore m_{2} = \frac{-1}{-5} = \frac{1}{5}$

iii) using the general equation for a line y = mx + c and substituting $m_{2}$ value and the value of a and y given by the co-ordinates through which the line passes

therefore we get

  $9 = \frac{1}{5} \times 5 + c \Rightarrow 9 = 1 + c \therefore c = 8$

Therefore the equation of the line required is given by $y = \frac{1}{5} x + 8$