Answer:
Yes, F is a continuous function of r
Step-by-step explanation:
We are given that
When r<R
[tex]F(r)=\frac{GMr}{R^3}[/tex]
[tex]r\geq R[/tex]
[tex]F(r)=\frac{GM}{r^2}[/tex]
Where M=Mass of the earth
R=Radius of earth
G=Gravitational constant
We have to find the function is continuous of r or not.
LHL
[tex]\lim_{r\rightarrow R-}\frac{GMr}{R^3}=\frac{GMR}{R^3}=\frac{GM}{R^2}[/tex]
RHL
[tex]\lim_{r\rightarrow R+}\frac{GM}{R^2}=\frac{GM}{R^2}[/tex]
[tex]F(R)=\frac{GM}{R^2}[/tex]
When a function is continuous at x=a
Then, LHL=RHL=f(a)
RHL==LHL=F(R)
Hence, the function is continuous of r.