Question

Orangutans can move by brachiation, swinging like a pendulum beneath successive handholds. If an orangutan has arms that are 0.90 m long and repeatedly swings to a 20° angle, taking one swing immediately after another, estimate how fast it is moving in m/s.

Answer 1

Answer:

how fast it is moving in m/s? 0.65 m/s.

Explanation:

given information:

the length of the arm, L - 0.9 m

angle, θ = 20°

First we calculate the distance in horizontal motion

s = 2 L sin θ

  = 2 (0.9) sin 20°

  = 0.62 m

now calculate the time

t/2 = 2π√(L/g)

t   = π√(0.9/9.8)

    = 0.95 s

the speed is

v = s/t

  = 0.62/0.95

  = 0.65 m/s