Respuesta :
Answer:
246.67 min
Explanation:
Half life is the time at which the concentration of the reactant reduced to half.
Half life expression for first order kinetic is:
[tex]t_{1/2}=\frac {ln\ 2}{k}[/tex]
Where, k is rate constant
So,
Given that;- k = [tex]2.81\times 10^{-3}\ min^{-1}[/tex] (Values corrected from source)
Thus,
[tex]t_{1/2}=\frac{\ln2}{2.81\times 10^{-3}\ min^{-1}}=\frac{\ln2}{2.81\times 10^{-3}}\ min[/tex]
[tex]t_{1/2}==355.87188\ln \left(2\right)\ min=246.67\ min[/tex]
246.67 min is the half-life of the reaction.
Answer:
t(1/2) = 246.67 min
Explanation:
a: SO2Cl2
⇒ - ra = k(Ca)∧α = - δCa/δt
∴ k = 2.81 E-3 min-1
∴ α = 1
⇒ Ln(Cao/Ca) = k*t
half-life of the reaction:
∴ Ca = (1/2)Cao
⇒ Ln (2) = (2.81 E-3 min-1)*t
⇒ t (1/2) = ( 0.6931 ) / ( 2.81 E-3 min-1 )
⇒ t (1/2) = 246.67 min
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