Question

A technical machinist is asked to build a cubical steel tank that will hold 230L of water.Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest 0.001m.

Answer 1

Answer:

0.613 meters is the smallest possible inside length of the tank.

Explanation:

Length of the cubical steel tank =- l

Volume of the cube = $l^3$

Volume of cubical steel tank = $230 L = 230\times 0.001 m^3$

$1 L = 0.001 m^3$

$V=l^3$

$230\times 0.001 m^3=l^3$

Solving of l :

$l=0.6127 m\approx 0.613 m$

0.613 meters is the smallest possible inside length of the tank.