The following six independent length measurements were made (in feet) for a line: 736.352, 736.363, 736.375, 736.324, 736.358, and 736.383. Determine the most probable value.

Respuesta :

Answer:

a) [tex]\bar X =\frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359[/tex]

b) The sample deviation is calculated from the following formula:

[tex]s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]

And for this case after replace the values and with the sample mean already calculated we got:

[tex] s= 0.0206[/tex]

If we assume that the data represent a population then the standard deviation would be given by:

[tex]\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}[/tex]

And then the deviation would be:

[tex] \sigma=0.0188[/tex]

Step-by-step explanation:

For this case we have the following dataset:

736.352, 736.363, 736.375, 736.324, 736.358, and 736.383

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

[tex] \bar X =\frac{\sum_{i=1}^n X_i}{n}[/tex]

And if we replace we got:

[tex]\bar X =\frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359[/tex]

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

[tex]s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]

And for this case after replace the values and with the sample mean already calculated we got:

[tex] s= 0.0206[/tex]

If we assume that the data represent a population then the standard deviation would be given by:

[tex]\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}[/tex]

And then the deviation would be:

[tex] \sigma=0.0188[/tex]

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