A 12.8-kg monkey hangs from a cord suspended from the ceiling of an elevator. The cord can withstand a tension of 156N and breaks as the elevator accelerates. What was the magnitude of the elevator's minimum acceleration? and What was the direction of the elevator's minimum acceleration?

Respuesta :

Answer:

[tex]2.4 m/s^2[/tex]

Downward

Explanation:

We are given that

Mass of monkey=12.8 kg

Tension=156 N

We have to find the magnitude of the elevator's minimum acceleration.

[tex]T=m(g+a)[/tex]

Where [tex]g=9.8 m/s^2[/tex]

Substitute the values

[tex]156=12.8(a+9.8)[/tex]

[tex]9.8+a=\frac{156}{12.8}=12.2 [/tex]

[tex]a=12.2-9.8=2.4 m/s^2[/tex]

Hence, the acceleration =[tex]a=2.4 m/s^2[/tex]

Direction of the elevator's minimum acceleration is downward because the elevator moves downwards.

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