Answer:
Acceleration=a=24.9 m/s^2≅[tex]25\ m/s^2[/tex]
Acceleration in g's:
Acceleration=24.9/9.8=2.54 g's
Explanation:
Given:
Revolutions= 3.0 revolutions per second
Distance from the axis of spin=7.0 cm=0.07 m
Required:
Radial acceleration (in m/s^2 and in g’s) of the endolymph fluid=?
Solution:
Time for one revolution:
T=1/3 rev=0.333 sec
Distance= Speed*Time
Speed=Distance/Time
Distance=2πR
[tex]Speed=v=\frac{2\pi R}{T}\\Speed=v=\frac{2\pi*0.07}{0.333} \\Speed=v=1.32079 m/s[/tex]
Acceleration in circular Path:
[tex]a=\frac{v^2}{R} \\a=\frac{1.32079^2}{0.07}\\a= 24.9 m/s^2[/tex]
Acceleration=a=24.9 m/s^2≅[tex]25\ m/s^2[/tex]
Acceleration in g's:
Acceleration=24.9/9.8=2.54 g's