Question

Which statements regarding the Henderson-Hasselbalch equation are true? 1) If the pH of the solution is known as is the pKa for the acid, the ratio of conjugate base to acid can be determined.2) At pH = pKa for an acid, there is an equal amount of conjugate base to acid in solution.3) At pH >> pKa for an acid, the acid will be mostly ionized.4) At pH << pKa for an acid, the acid will be mostly ionized. a. 1, 2, and 3 are true.b. 2, 3, and 4 are true.c. 1, 2, and 4 are true.d. All of the listed statements are true.

Answer 1

Answer:

A

Explanation:

Using Henderson-Hasselbalch equation

pH = pKa + log (A⁻ (base)) / ( HA (acid))

1) if the pH of the solution is known as is the pKa for the acid , the ratio of the conjugate base to acid can be determined; it is true considering the formula above

2) At pH = pKa for an acid, there is an equal amount of conjugate base to acid in the solution; this is also true because at pH = pKa, the log of the ratio of the conjugate base to acid equal to zero and antilog of zero is 1 which means their proportion is  the same.

3) At pH  > pKa for an acid, the acid will be mostly ionized; this is true also  the solution high amount of deprotonated form of the acid.

Answer 2

Correct answer is a.

Henderson-Hasselbalch equation

$pH = pKa + log (A^{-} (base)) / ( HA (acid))$

1) if the pH of the solution is known as is the pKa for the acid , the ratio of the conjugate base to acid can be determined; it is true considering the formula above.

2) At pH = pKa for an acid, there is an equal amount of conjugate base to acid in the solution; this is also true because at pH = pKa, the log of the ratio of the conjugate base to acid equal to zero and antilog of zero is 1 which means their proportion is  the same.

3) At pH  > pKa for an acid, the acid will be mostly ionized; this is true also  the solution high amount of deprotonated form of the acid.

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