Answer:
Ka for acetic acid = [tex]1.8\times 10^{-5}[/tex]
Ka for trichloro acetic acid is 0.2
Explanation:
Given that:-
pKa of acetic acid is 4.76
The expression for the relation between pKa and Ka is shown below as:-
pKa = - log Ka
So,
[tex]Ka = 10^{-pKa}[/tex]
Applying the values as:-
[tex]Ka = 10^{-4.76}=1.8\times 10^{-5}[/tex]
For, trichloro acetic acid, pKa= 0.7
SO,
[tex]Ka = 10^{-0.7}=0.2[/tex]