Answer:
6Ω
Explanation:
The 6Ω resistor and the 3Ω resistor are in parallel.
R = 1 / (1/6 + 1/3)
R = 1 / (1/6 + 2/6)
R = 1 / (3/6)
R = 6/3
R = 2
The 8Ω resistor and the other 8Ω resistor are also in parallel.
R = 1 / (1/8 + 1/8)
R = 1 / (2/8)
R = 8/2
R = 4
This 4Ω resistance is in series with the 4Ω resistor.
R = 4 + 4
R = 8
The 2Ω resistor and the 6Ω resistor are also in series.
R = 2 + 6
R = 8
These two 8Ω resistances are in parallel.
R = 1 / (1/8 + 1/8)
R = 1 / (2/8)
R = 8/2
R = 4
Finally, this 4Ω resistance is in series with the 2Ω resistance we found earlier.
R = 4 + 2
R = 6
The total equivalent resistance is 6Ω.
