Question

calculate a balloon has a volume of 1.5-liters at 25.0 degrees Celsius. what would be the volume of the balloon if it were placed in a container of hot water at 90.0 degrees celsius?

Answer 1

Answer:

The answer to your question is 1,83 L

Explanation:

Data

Volume 1 = V1 = 1.5 l

Temperature 1 = T1 = 25°C

Volume 2 = V2 = ?

Temperature 2 = T2 = 90°C

Process

1.- Convert temperature °C to °K

Temperature 1 = 25° + 273 = 298°K

Temperature 2 = 90° + 273° = 363°K

2.- Use the Charles' law to solve this problem

                                $\frac{V1}{T1} = \frac{V2}{T2}$

Solve for V2

                               $V2 = \frac{V1T2}{T1}$

Substitution

                               $V2 = \frac{(1.5)(363)}{298}$

Simplification

                              $V2 = \frac{544.5}{298}$

Result

                              V2 = 1.83 L