Question

As a contrast between the old and the modern and between the large and the small, consider the following: In old rural England 1 hide (110 acres) was the area of land needed to sustain one family with a single plough for one year. (An area of 1 acre is equal to 4047 m2.) Also, 1 wapentake was the area of land needed by 100 such families. In quantum physics, the cross-sectional area of a nucleus (defined in terms of the chance of a particle hitting and being absorbed by it) is measured in units of barns, where 1 barn is 1 × 10-28 m2 (exactly). (In nuclear physics jargon, if a nucleus is "large," then shooting a particle at it is like shooting a bullet at a barn door, which can hardly be missed.) What is the ratio of 26 wapentakes to 18 barns?

Answer 1

Answer:

$6.43023\times 10^{35}$

Explanation:

1 Wapentake

$1\ Wapentake=110\times 4047\times 100=44517000\ m^2$

1 barn

$1\ barn=1\times 10^{-28}\ m^2$

The ratio

$\dfrac{26\ Wapentake}{18\ barn}$

$=\dfrac{26\times 44517000}{18\times 1\times 10^{-28}}=6.43023\times 10^{35}$

The required ratio is $6.43023\times 10^{35}$