Question

Assemble the proof by dragging tiles to the statements and reasons columns.

Answer 1

Answer:

Step-by-step explanation:

Given;

Δ QPR ≅ ∠ STR

 i)  $\frac{QP}{ST} = \frac{QR}{SR} = \frac{PR}{TR}$

ii )∠ PRQ = ∠ TRS     ( Both are 90° since QR ⊥ PT )

iii) ∠ RPQ = ∠ STR     ( same side ratio from (i) )

Hence it is proved that

Δ PQR $\sim$ Δ TSR

Answer 2

The $\triangle PQR$ is similar to $\triangle TSR$ using the AAA properties for similar triangle.

Given to us:

$\overline{QR} \perp \overline{PT}$ , So, we can write that $\angle PRQ = \angle TRS=90^o$;

$\angle QPR \cong \angle STR$;

Also we  know that sum of all the angles of a triangle is 180°. So,

$(\angle QPR +\angle PRQ +\angle RQP) = (\angle STR +\angle TRS + \angle RST) = 180^o$

$\angle RQP = \angle RST$

Therefore, using the AAA (Angle Angle Angle) properties for similar triangle. All three pairs of corresponding angles are the same.

Hence, $\triangle PQR \sim \triangle TSR$.

To know more visit:

https://brainly.com/question/25882965