Question

How many moles of glucose can be produced
from a photosynthesis reaction
6 CO2(g) + 6H2O(0)
C6H12O6(aq) + 6 O2(g)
that occurs using 13.9 mol CO2?

Answer 1

Answer:

moles of glucose

2.3166 moles of glucose

Explanation:

The balance reaction for the formation of glucose is :

$6CO_{2}+6H_{2}O\rightarrow C_{6}H_{12}O_{6}+6O_{2}$

here , CO2 = carbon dioxide

H2O = water

C6H12O6 = glucose

O2 = Oxygen

According to this equation :

6 mole of CO2 = 6 mole of H2O = 1 mole of C6H12O6 = 6 mole of O2

We are asked to calculate the mole of Glucose from carbon dioxide.

So,

6 mole of CO2  produce = 1 mole of C6H12O6

1 mole of CO2 will produce =

$\frac{1}{6}$ moles of glucose

13.9 moles of CO2 will produce :

$\frac{1}{6}\times 13.9$

=2.3166 moles of glucose

Note : first , Always calculate for one mole (By dividing)

. After this , multiply the answer with the moles given.

Always write the substance whose amount is asked(glucose) to the right hand side