Answer:
Therefore Mason would be expected to win 50 times.
Step-by-step explanation:
i) probability of flipping a head for a fair coin is [tex]\frac{1}{2}[/tex]
ii) probability of flipping two fair coins is = [tex]\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}[/tex]
iii) Therefore if Mason plays 200 times he would be expected to win
= [tex]\frac{1}{4} \times 200 = 50\hspace{0.1cm} times.[/tex]
