(d) A and B above
=> Writing option a in a well-formatted way, we have:
String str1 = "Golden";
String str2 = "Retriever";
if (str1.equals(str2))
System.out.println("Golden Retriever!");
Lines 1 and 2 of the code correctly assign the strings "Golden" and "Retriever" to the String variables str1 and str2 respectively. This will raise no error.
Line 3 checks if the value of variables str1 and str2 are the same. This is a correct way of checking. Therefore, there will be no error.
Line 4 prints out the string "Golden retriever" depending on whether or not the condition is the if statement is true. Since it is not true, this will not be printed. That is not bad as no error will be thrown.
Therefore, the code in option a will not throw any error.
=> Writing option b in a well-formatted way, we have:
String str1 = "Golden";
String str2 = str1.substring(4);
System.out.println(str1 + str2);
Line 1 of the code above correctly assigns the string "Golden" to the String variable str1. This will not raise any error.
Line 2 of the code correctly assigns to the String variable str2, the substring of str1("Golden") starting from the 4th index. i.e "en". This will raise no error.
Line 3 of the code prints out the result of the concatenation of the values of str1 and str2 which is "Golden" + "en" = "Goldenen"
Therefore, the code in option b will not throw any error either.
Therefore, A and B above will not raise an error when they are executed.
Incorrect code segments will through exception errors, during program execution.
The correct statement is (d) A and B above
The statements are given as:
The first statements correctly check if both strings are equal
The second statements correctly print str1 and the 4th index of string 2
This mean that both statements will run without throwing exception errors.
Hence, the correct statement is (d)
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