Question

A volcano launches a lava bomb straight upward with an initial speed of 26 m/s .A Taking upward to be the positive direction, find the velocity of the lava bomb 2.0 seconds after it is launched.B. Taking upward to be the positive direction, find the direction of motion of the lava bomb 2.0 seconds after it is launched.
C. Taking upward to be the positive direction, find the velocity of the lava bomb 3.0 seconds after it is launched.
D. Taking upward to be the positive direction, find the direction of motion of the lava bomb 3.0 seconds after it is launched.

Answer 1

Answer:

6.38 m/s

going up

3.43 m/s

going down

Explanation:

t = Time taken

u = Initial velocity = 26 m/s

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s² = a (-ve up, +ve down)

$v=u+at\\\Rightarrow v=26-9.81\times 2\\\Rightarrow v=6.38\ m/s$

The velocity of the lava bomb 2 seconds later is 6.38 m/s going up

$v=u+at\\\Rightarrow v=26-9.81\times 3\\\Rightarrow v=-3.43\ m/s$

The lava ball will be coming down at 3.43 m/s