Answer:
Upright, Reduced
Explanation:
Given that,
Height of the object, h = 20 cm
Image distance, v = 25 cm
Height of the image, h' = 5 cm
We know that the magnification of the mirror is given by :
[tex]m=\dfrac{h'}{h}=\dfrac{v}{u}[/tex]
[tex]\dfrac{5}{20}=\dfrac{25}{u}[/tex]
u = -100 cm (negative due to sign conventions)
Let f is the focal length of the lens. It can be calculated as :
[tex]\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}[/tex]
[tex]\dfrac{1}{f}=\dfrac{1}{25}-\dfrac{1}{(-100)}[/tex]
f = 20 cm
It is seen that the focal length of the lens is positive. So, it is a convex lens. The image formed by the convex lens is Upright, Reduced. Hence, the correct option is (a).