Answer:
a) [tex] \phi (x) = a/(I/2) [/tex]
b) [tex] f(x) = 2/I [/tex]
Step-by-step explanation:
a) Lets denote [tex] \phi [/tex] the cumulative distribution function of X. Note that for any value a between 0 and I/2, we have that [tex] \phi(a) [/tex] is the probability for the stick to be broken before the length a is reached following the stick from one starting point plus the probability for the stick to be broken after the length I-a from the same starting point. This means that [tex] \phi(a) = (a+a)/I = 2a/I = a/ (I/2) [/tex]
b) Note that, as a consecuence of what we calculate in the previous item, X has a uniform distribution with parameter I/2, therefore, the probability density function f is
f(x) = 1/(I/2) = 2/I