How many moles of calcium chloride are theoretically produced for the following reaction given we have 2.6 moles of HCl and 1.4 moles of Ca(OH)2? Reaction: 2HCl + Ca(OH)2 → 2H2O + CaCl2

Respuesta :

Answer : The number of moles of calcium chloride theoretically produced are, 1.3 moles.

Explanation : Given,

Moles of HCl = 2.6 moles

Moles of [tex]Ca(OH)_2[/tex] = 1.4 moles

Now we have to calculate the limiting and excess reagent.

The given balanced chemical reaction is:

[tex]2HCl+Ca(OH)_2\rightarrow 2H_2O+CaCl_2[/tex]

From the balanced reaction we conclude that

As, 2 mole of [tex]HCl[/tex] react with 1 mole of [tex]Ca(OH)_2[/tex]

So, 2.6 moles of [tex]HCl[/tex] react with [tex]\frac{2.6}{2}=1.3[/tex] moles of [tex]Ca(OH)_2[/tex]

From this we conclude that, [tex]Ca(OH)_2[/tex] is an excess reagent because the given moles are greater than the required moles and [tex]HCl[/tex] is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of [tex]CaCl_2[/tex]

From the reaction, we conclude that

As, 2 mole of [tex]HCl[/tex] react to give 1 mole of [tex]CaCl_2[/tex]

So, 2.6 moles of [tex]HCl[/tex] react to give [tex]\frac{2.6}{2}=1.3[/tex]moles of [tex]CaCl_2[/tex]

Therefore, the number of moles of calcium chloride theoretically produced are, 1.3 moles.

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