Answer : The number of moles of calcium chloride theoretically produced are, 1.3 moles.
Explanation : Given,
Moles of HCl = 2.6 moles
Moles of [tex]Ca(OH)_2[/tex] = 1.4 moles
Now we have to calculate the limiting and excess reagent.
The given balanced chemical reaction is:
[tex]2HCl+Ca(OH)_2\rightarrow 2H_2O+CaCl_2[/tex]
From the balanced reaction we conclude that
As, 2 mole of [tex]HCl[/tex] react with 1 mole of [tex]Ca(OH)_2[/tex]
So, 2.6 moles of [tex]HCl[/tex] react with [tex]\frac{2.6}{2}=1.3[/tex] moles of [tex]Ca(OH)_2[/tex]
From this we conclude that, [tex]Ca(OH)_2[/tex] is an excess reagent because the given moles are greater than the required moles and [tex]HCl[/tex] is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of [tex]CaCl_2[/tex]
From the reaction, we conclude that
As, 2 mole of [tex]HCl[/tex] react to give 1 mole of [tex]CaCl_2[/tex]
So, 2.6 moles of [tex]HCl[/tex] react to give [tex]\frac{2.6}{2}=1.3[/tex]moles of [tex]CaCl_2[/tex]
Therefore, the number of moles of calcium chloride theoretically produced are, 1.3 moles.