Answer:
The triangles Δ VWZ and Δ VXY are similar by AA criteria.
Step-by-step explanation:
See the attached diagram.
Here, VZ = 16 in and ZY = 8 in. Again, VW = 18 in and WX = 9 in.
Therefore, [tex]\frac{VZ}{ZY} = \frac{VW}{WX} = \frac{2}{1} = 2[/tex]
So, line WZ divides the lines VY and VX in the same ratio 2 : 1.
So, Line WZ ║ Line XY
Hence, ∠ XYV = ∠ WZV {The corresponding angles as VY is a transverse}
Again, ∠ YXV = ∠ ZWV {The corresponding angles as VX is a transverse}
Therefore, the triangles Δ VWZ and Δ VXY are similar by Angle-Angle i.e. AA criteria. (Answer)