Respuesta :
Answer:
a different inverse function
Step-by-step explanation:
If [tex]f^{-1}(x)=-\frac{1}{5}x[/tex] then [tex]f^{-1}(x)=\frac{1}{5}x[/tex] is a different inverse function.
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The second (inverse) function is the first reflected over the y-axis.
The inverse of a function is the direct opposite of the function.
[tex]f^{-1}(x) = \frac 15[/tex] is an inverse function.
The function is given as:
[tex]f^{-1}(x) = \frac 15[/tex]
For a function f(x), its inverse is given as: [tex]f^{-1}(x)[/tex].
This means that the function [tex]f^{-1}(x) = \frac 15[/tex] represents an inverse function of f(x).
Where:
[tex]f(\frac{1}{5}) = x[/tex]
Hence, [tex]f^{-1}(x) = \frac 15[/tex] is an inverse function.
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